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What is the density of lead (in g/cm3) if a rectangular bar measuring 0.50 cm in height, 1.55 cm in width, and 25.00 cm in length has a mass of 218.9 g ? express your answer using two significant figures?

User Salmo
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2 Answers

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if you look at the units of density, g/cm^3 you will see it's grams divided by volume (cm^3).

218.9 g / (0.5*1.55*25 cm^3) = 11.3 g/cm^3
User Oleg Shaldybin
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3 votes

Answer:

Step-by-step explanation:

density is defined as the measure of the mass of a matter per unit volume. it describes the sopace occupied by a substance relative to its volume.

Density = mass ÷ volume

ρ = m ÷ v

Volume = length × width × height

Volume of lead bar = l × w × h

V = 25 × 1.55 × 0.5

V = 19.375cm³

mass of bar = 218.9g

ρ = 218.9 ÷ 19.375

ρ = 11.2980g/cm³

ρ = 11g/cm³

User Mark Probst
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