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To determine a 72 percent level of confidence for a proportion, the value of z is approximately:

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To solve this problem, we have to make use of the standard probability distribution tables for z test.

Since we are asked to find for the 72 percent level confidence, then this means we are to look for the value of z which gives (100-72)/2 = 14% on both sides of the tail.

So at 14% tail on one side, the z value is approximately:

1.08

Answer:

± 1.08

User Yanigisawa
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