Question

A gas has a Pressure of 20 Atm and a volume of 10 L. If the Pressure increases to 30 Atm, what is the new volume?

Answer 1

6.67L

Explanations:

According to Boyle's law, the pressure of a given mass is inversely proportional to its volume provided that the temperature remains constant. Mathematically;

`\begin{gathered} p\alpha(1)/(v) \\ p=(k)/(v) \\ pv=k \\ p_1v_1=p_2v_2 \end{gathered}`

where:

• p₁ and p₂ are the, initial and fina,l pressure

,

• v₁ and v₂ are the ,initial and final volume

Given the following parameters

p₁ = 20atm

p₂ = 30atm

v₁ = 10L

Required

new volume v₂

Substitute the given parameters into the formula to have;

`\begin{gathered} v_2=(p_1v_1)/(p_2) \\ v_2=\frac{20\cancel{\text{atm}}*10L}{30\cancel{\text{atm}}} \\ v_2=(200)/(30)L \\ v_2=6.67L \end{gathered}`

Therefore the new volume of the gas is 6.67L