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I^89 simplified. Complex number.

User Reigo Hein
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1 Answer

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This problem can be simplified by remembering that since
i= √(-1), we have
i^(4)=(-1)^(2)=1. Then we have
i^(89)=i^(88+1)=i^(88)i^(1)=(i^(4))^(22)i=(1)^(22)i=i.

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