Question

10 Points.) A stone weighing 0.7 kilograms rolls down the inclined plane from position B to position A. Position A is located at sea level. The Inclined Plane is 0.25 Meters high.  The difference in the gravitational potential energy of the ball between positions A and B is about___ joules. (Use PE = m × g × h, where g = 9.8 N/kg.)

Answer 1

1.715 Joules

Step-by-step explanation:

ΔPE = m * g * Δh = 0.7 kg * 9.8 N/kg * 0.25 m = 1.715 N*m = 1.715 J

Answer 2

Given that there is not figure with the plane and positions, I assume the data are self-explanatorye.

So,

Position A = sea level = 0 m

Postion B = 0.25 m

Difference in the gravitational potential energy of the ball between positions A and B:

ΔPE = m * g * Δh = 0.7 kg * 9.8 N/kg * 0.25 m = 1.715 N*m = 1.715 J

Answer: 1.715 J