Question

What is an equation in point-slope form of the line shown below(i will drop a picture)

Answer 1

In the given graph of line : the two coordinates are : (-4,1) and (4, -3)

The standard form of point-slope form of the line is :

`y\text{ = }(y_2-y_1)/(x_2-x_1)(x-x_1)+y_1`

Substitute the coordinates : ( -4, 1) & ( 4, - 3)

`\begin{gathered} y\text{ = }(y_2-y_1)/(x_2-x_1)(x-x_1)+y_1 \\ \text{Substitute x}_1=-4,x_2=4,y_1=1andy_2=-3 \\ y=(-3-1)/(4-(-4))(x-(-4))+1 \\ y=(-4)/(4+4)(x+4)+1 \\ y=(-4)/(8)(x+4)+1 \\ y=(-1)/(2)(x+4)+1 \\ y-1=-(1)/(2)(x+4) \end{gathered}`

Answer : A)

`y-1\text{ = -}(1)/(2)(x+4)`