Question

Let f ( x ) = 2 x − 1 , g ( x ) = 3 x , and h ( x ) = x ^2 + 1 , what is g (h( 24 ) ) ?

Answer 1

You must calculate h(24) first. h(x) = x^2 + 1, so h(24) = 577.

g(x) = 3x, so g(577) = 3(577) = 1731 (answer). We don't need f(x).