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Mick has a bag with 2 mint sticks, 11 jelly treats, and 7 fruit tart chews. If he eats one piece every 10 minutes, what is the probability his first two pieces will be a jelly treat and a mint stick?

Give your answer in a percent.

User Kxc
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2 Answers

4 votes

Final answer:

To find the probability, calculate the probabilities of selecting a jelly treat and a mint stick. Then multiply these probabilities together to find the overall probability.

Step-by-step explanation:

To find the probability that Mick's first two pieces will be a jelly treat and a mint stick, we need to calculate the probability of selecting a jelly treat and a mint stick from the bag.

First, we need to find the total number of pieces in the bag: 2 mint sticks + 11 jelly treats + 7 fruit tart chews = 20 pieces.

The probability of selecting a jelly treat as the first piece is: 11 jelly treats / 20 total pieces = 0.55 or 55%.

After Mick has eaten one piece, there are now 19 pieces left in the bag.

The probability of selecting a mint stick as the second piece is: 2 mint sticks / 19 remaining pieces = 0.105 or 10.5%.

Therefore, the probability that Mick's first two pieces will be a jelly treat and a mint stick is 55% * 10.5% = 0.055 or 5.5%.

User Aliasav
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6 votes
first you add all the candies together to get 20 in the bag
2+11+7=20

jelly treat:
now we divide 11 by 20 to get a decimal
11/20= .55

multiply .55 by 100 to change it to a percentage
.55*100=55

first part of answer: He has a 55% chance of getting a jelly treat

mint stick:
divide 2 by 20 to get a decimal
2/20=.1

change .1 to a percent by multiplying by 100
.1*100=10

second part of answer: he has a 10% chance of getting a mint stick
User Pxwise
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