Question

What is the molality of a solution that has 3 mol of glucose in 6 kg of water?

Answer 1

it is 3/6 = 0.5 mol/kg of solvent i.e. 0.5 molal solution

Answer 2

Answer: 0.5 m

Step-by-step explanation:

Molality : It is defined as the number of moles of solute present per kg of solvent

Formula used :

`Molality=(n* 1000)/(W_s)`

where,

n= moles of solute

Moles of glucose = 3 moles

`W_s` = weight of solvent (water) in g = 6 kg = 6000 g (1kg=1000g)

Now put all the given values in the formula of molality, we get

`Molality=(3moles* 1000)/(6000g)=0.5mole/kg`

Therefore, the molality of solution will be 0.5 mole/kg.