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Problem number 7 trigonometry

Problem number 7 trigonometry-example-1
User Vietstone
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7) - 1

tan <BAD = BD / AD

BC = √(64 + 36)
BC = √100
BC = 10

now you can solve BD
BD/6 = 6/10
BD = 6*6 / 10
BD = 36/10
BD = 3.6

AD = √36 - 12.96
AD = √23.04
AD = 4.8

tan <BAD = BD / AD
tan <BAD = 3.6 / 4.8
tan <BAD = 0.75

7) - 2

cos <DAC + cos <DAB

as you know cos = Adj / Hypo

cos <DAC = AD/AC
cos <DAC = 4.8 / 8
cos <DAC = 0.6

cos <DAB = AD / AB
cos <DAB = 4.8/6
cos <DAB = 0.8

so
cos <DAC + cos <DAB = 0.6 + 0.8
cos <DAC + cos <DAB = 1.4

hope it helps


User Taynguyen
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