Question

The perimeter, P, of a rectangle is the sum of twice the length and twice the width.

P = 2(l+w) units
P = 2(5)+2(9) units
P = 4x units
P = (l+l)+(w+w) units
P = 2(x+3) units

Answer 1

The answer is P = 2(l+w) units.

This is because when you let the perimeter of the rectangle be P, the length of the rectangle be l and the width of the rectangle be w.

The information above can be expressed as the following equation,
P = 2l + 2w

You can then factorise out the common factor, 2.
P = 2(l+w)

Thus, the answer is P = 2(l+w) units.

Answer 2

P=2(l+w)

Explanation:

It is given that perimeter, P, of a rectangle is the sum of twice the length and twice the width.

Let length of rectangle is l and width of the rectangle is w.

Perimeter = 2 × Length + 2 × Width

`P=2* l+2* w`

`P=2l+2w`

Taking out common factors.

`P=2(l+w)`

[Note: (l+l)+(w+w) units is also true but according to the statement only option 1 is true]

Therefore, the correct option is 1.