Question

the larger of two numbers is nine less than four times the smaller number. If the sum od the two numbers is 76, find both numbers

Answer 1

x = larger number
y = smaller number

x = 4y - 9
x + y = 76

4y - 9 + y = 76
5y = 76 + 9
5y = 85
y = 85/5
y = 17

x + y = 76
x + 17 = 76
x = 76 - 17
x = 59

ur numbers are 17 and 59

Answer 2

17 and 59

Explanation:

Let's find the answer by assuming the following:

L=larger number

S=smaller number

The first condition is: 'L' is nine less than four times 'S' but, because:

(four times 'S') is the same as 4*S then:

('L' is nine less than four times 'S') is equal to ('L' is nine less than 4*S), which means:

L+9=4*S (eq. 1)

Second condition is: the sum of the two numbers is 76, so:

L+S=76 which can be written as:

S=76-L using this relation in eq. 1 we have:

L+9=4*S

L+9=4*(76-L)

L+9=304-4L

L+4L=304-9

5L=295

L=295/5

L=59

And also we have:

L+S=76

S=76-L

S=76-59

S=17

In conclusion, the two numbers are 17 and 59.