1 Answer

Chris Harrington · Answer 1 · 2018-03-17T11:49:10+0000

a(n) = 9.(-1/3)ⁿ⁻¹

for n = 1; a₁ = 9.(-1/3)⁰ = 9.(1) = 9

for n=2 , a₂ = 9.(-1/3)¹ = -9/3 = -3 or a₂ = a₁.(-1/3)¹

for n=3 ; a₃ = 9.(-1/3)² =9/9 =1 or a₃ = a₂.(-1/3)²

so a₁ =9 and

a(n) = a(n-1)(-1/3) (ANSWER A)

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