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Cassidy wrote the linear equation y=5x+4 Then, she wrote the equation of the line that is parallel to y=5x+4 and that passes through (8,–2). If her new equation is in the form y=5x+b what is the value
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Cassidy wrote the linear equation y=5x+4 Then, she wrote the equation of the line that is parallel to y=5x+4 and that passes through (8,–2). If her new equation is in the form y=5x+b what is the value of b? please helpppp

User Jay Wick
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well, again y=5x+4 is in slope-intercept form, therefore
\bf y=\stackrel{slope}{5}x+4.

so then, a parallel line to a line with that equation, will also have the same slope, therefore, what's the equation of a line whose slope is 5 and goes through 8, -2?


\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{8}}\quad ,&{{ -2}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies 5 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-2)=5(x-8)\implies y+2=5x-40 \\\\\\ y=5x-40-2\implies y=5x-42
User Medhi
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