164k views
3 votes
How much energy is required to heat 32.5 g of water from 34°C to 75°C

User Nighil
by
8.0k points

1 Answer

2 votes
Q = mc (delta T) = 32.5 x 1 x (75-34) = 1332.5 cal
User Giraff
by
8.6k points