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How can I factor 27x³ 64=0?

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You need to memorize how to factor cube roots, i.e. x^3 - y^3 or x^3 + y^3.
You left a + or - sign out but:

Here you have the difference of 2 cubes.
Then (3x - 4)( 9x^2 + 12x + 16)
or (3x+ 4)( 9x^2 - 12x + 16)
User Rajamohan S
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