Question

The highest speed achieved by a standard non racing sports car is 350km/h. Assuming that the car accelerates at 4.00m/s2,how long would this car take it’s maximum speed of its initially at rest. What distance would the car travel during this time

Answer 1

The distance traveled by the car during this time is 1.18 km.

Step-by-step explanation:

Initial speed of the car, u = 0 (at rest)

Final sped of the car,
`v=350\ km/h = 97.23\ m/s`

Acceleration of the car,
`a=4\ m/s^2`

We need to find the distance would the car travel during this time. It can be calculated using third equation of motion. It is given by :

`v^2-u^2=2ad`

`v^2=2ad`

`d=(v^2)/(2a)`

`d=((97.22\ m/s)^2)/(2* 4\ m/s^2)`

d = 1181.46 m

or

d = 1.18 km

So, the distance traveled by the car during this time is 1.18 km. Hence, this is the required solution.

Answer 2

The first part is pretty straight forward, vₓ=v₀+a(t). Convert final velocity to m/s to get 97.2m/s. v₀=0, a=4. Solving for t yields 24.3 seconds.

For the second part use "vₓ^2(final velocity) = v₀^2(initial velocity) + 2a(Δx). Final velocity is 97.2m/s, initial velocity is 0, acceleration is 4m/s^2. Solving for Δx yields 1181.53 meters.