225,345 views
32 votes
32 votes
How many moles of potassium are needed to react completely with 12.8 moles of magnesium bromide?

How many moles of potassium are needed to react completely with 12.8 moles of magnesium-example-1
User Helder Sepulveda
by
2.7k points

1 Answer

22 votes
22 votes

Answer:

25.6 moles of K.

Step-by-step explanation:

In the chemical equation you can see that 2 moles of potassium (K) react with 1 mol of magnesium bromide (MgBr2), so based on this information let's find the number of moles of K that we required by 12.8 moles of MgBr2:


12.8\text{ moles MgBr}_2\cdot\frac{2\text{ moles K}}{1\text{ mol MgBr}_2}=25.6\text{ moles K.}

The answer would be that we require 25.6 moles of K.

User Akinyele
by
2.9k points