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How would you solve #3?
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How would you solve #3?
asked
Feb 15, 2018
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How would you solve #3?
Mathematics
high-school
TechArcSri
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1
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3)
Perimeter of square = 4a
P = 4a
so
a = P/4
a = (12x^5 - 8x^2 + 20x - 4)/ 4
a = 3x^5 - 2x^2 + 5x - 1
answer
side = 3x^5 - 2x^2 + 5x - 1
Gorkk
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Feb 19, 2018
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Gorkk
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