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34 votes
Given y = f(u) and u = g(x), find = f’(g(x))g’(x).y = 8u+ 3, U=(1/2)x^8Dy/dx=

User Aksn
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1 Answer

23 votes
23 votes

\begin{gathered} y=f(u)=8u+3 \\ u=((1)/(2))x^8 \end{gathered}

so:


\begin{gathered} y=8((1)/(2)x^8)+3 \\ y=4x^8+3 \end{gathered}
\begin{gathered} (dy)/(dx)=4(8x^(8-1))+0 \\ (dy)/(dx)=12x^7 \end{gathered}

Power rule

User Charbel
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