Question

a man stands on a flat surface and shoots an arrow vertically into the sky at avelocity of 60 meters per second. calculate the maximum height the arrow reached. what was the velocity of the car when it hit the ground?

Answer 1

a) Vi= 60 m/s
a= -9.81 m/s^2
Vf= 0m/s^2
d=?

Vf^2=Vi^2+2ad
(0m/s)^2=(60m/s)^2+2(-9.81m/s^2)d
0=3600+(-19.62)d
-3600=(-19.62)d
(-3600)/(-19.62)=(-19.62)d/(-19.62)
d=183.5m

c) Vi= 60 m/s
a= -9.81 m/s^2
Vf= 0m/s^2
t=10s
d=?

d=Vi*t+(1/2)a*t^2
d=60m/s(10s)+(1/2)(-9.81m/s^2)(10s)^2
d=600+(-4.905)(100)
d=600+(-490.5)
d=108.5m