Question

If a 1.50 kg mass revolves at the end of a string 0.50 m long, and its tangential speed is 6.0 m/s, calculate the centripetal force.

Answer 1

You should get about 110 for an answer

Answer 2

`108\ N`

Step-by-step explanation:

Mass of object,
`m=1.50\ kg.`

Length of string,
`r=0.50\ m.`

Tangential speed,
`v_t=6.0\ m/s.`

Now, centripetal force F of a object moving in given radius r and mass m moving with velocity v.

Here , object moves along the ends of string. Therefore, radius is equal to length of string.

`F=(m * v_t^2)/(r).`

Putting values of m,v and r in above equation.

We get,
`F=(1.50* (6.0)^2)/(0.50) \ N=108 \ N.`

Hence, this is the required solution.