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A honey bee flaps its wings 200 times per second. How much time is required for one wingbeat? Give your answer in milliseconds.

User Xoxox
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A bees wings move so rapidly that studying them, even seeing them, has proved difficult.
The honeybees have a rapid wing beat honeybee flaps its wings 230 times every second.

Therefore, a bee flaps its wings over 200 times in about 1ms
User Florian Pilz
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Answer:

The time is required for one wing beat is 5 millisecond.

Step-by-step explanation:

Given that,

Frequency = 200 /sec

We need to calculate the time period

Using formula of time period

Time period is the reciprocal of the frequency.


T=(1)/(f)


T=(1)/(200)


T=0.005\ sec


T= 5\ miliseconds

Hence, The time is required for one wing beat is 5 millisecond.

User MECoskun
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