Alright, so if the first number is x, the second number is y, and the third number is z, we have x+y+z=270. Next, since we know that x=y-1 since it is less than y by one and z=y+1, we have y-1+y+y+1=y+y+y=3y=270. Dividing both sides by 3, we get y=90