Question

QuestionFind the intercepts of the parabola whose function is f (x) = x² – 4x– 12.

Answer 1

The intercepts of the parabola are at;

`(0,-12),(-2,0),(6,0)`

Step-by-step explanation:

Given the function:

`f(x)=x^2-4x-12`

The intercepts of the function would be at x=0 or y=0.

At x=0;

`\begin{gathered} y=f(0)=0^2-4(0)-12 \\ y=-12 \\ (0,-12) \end{gathered}`

at y=0;

`\begin{gathered} f(x)=x^2-4x-12=0 \\ x^2-4x-12=0 \\ (x+2)(x-6)=0 \\ x+2=0 \\ x=-2 \\ or \\ x-6=0 \\ x=6 \\ (-2,0),(6,0) \end{gathered}`

Therefore, the intercepts of the parabola are at;

`(0,-12),(-2,0),(6,0)`