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QuestionFind the intercepts of the parabola whose function is f (x) = x² – 4x– 12.

User Tinna
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1 Answer

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25 votes

Answer:

The intercepts of the parabola are at;


(0,-12),(-2,0),(6,0)

Step-by-step explanation:

Given the function:


f(x)=x^2-4x-12

The intercepts of the function would be at x=0 or y=0.

At x=0;


\begin{gathered} y=f(0)=0^2-4(0)-12 \\ y=-12 \\ (0,-12) \end{gathered}

at y=0;


\begin{gathered} f(x)=x^2-4x-12=0 \\ x^2-4x-12=0 \\ (x+2)(x-6)=0 \\ x+2=0 \\ x=-2 \\ or \\ x-6=0 \\ x=6 \\ (-2,0),(6,0) \end{gathered}

Therefore, the intercepts of the parabola are at;


(0,-12),(-2,0),(6,0)

User Fearnbuster
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