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Use this equation to find dy/dx. 3y cos x = x2 + y2

User Varnit
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Given: 3y cos x = x² + y²

Define
y' = (dy)/(dx)

Then by implicit differentiation, obtain
3y' cos(x) - 3y sin(x) = 2x + 2y y'
y' [3 cos(x) - 2y] = 2x + 3y sinx)

Answer:

(dy)/(dx) = (2x+3y \, sin(x))/(3cos(x)-2y)
User Nikki Chumakov
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