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Alficles · Answer 1 · 2018-08-27T23:32:33+0000

atomic mass of cl = 35.5 amu.

molar mass of ccl4 = (12) +4 (35.5)
= 12 + 142
= 154 amu.

mass of ccl4 = 385 g

no. of moles present = 385 / 154 = 2.5 mole
so, 2.5 mole of ccl4 is present in 385 grams .

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