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9 votes
Represent Real-World Problems A baseball "diamond" actually forms a square, each side measuring 30 yards. How far, to the nearest yard, must the third baseman throw the ball to reach first base?

User Inorganik
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1 Answer

17 votes
17 votes

where the red line is the distance solution

we can take a triangle, than has a right angle becase is from a square

so

and use pythagoras


\begin{gathered} 30^2+30^2=D^2 \\ D=\sqrt[]{30^2+30^2} \\ D=30\sqrt[]{2}\approx42.43 \end{gathered}

so, the distance is 42 yards

Represent Real-World Problems A baseball "diamond" actually forms a square-example-1
Represent Real-World Problems A baseball "diamond" actually forms a square-example-2
User Mathieu
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