Question

I have a calculus question about derivatives:
`\frac{ - 3sin(x)}{ 10x {}^1 {}^0{ - 6} {} }`

Answer 1

we have the expression

`(-3sin(x))/(10x^(10)-6)`

Applying the quotient rule

The derivative is equal to

`(-3s\imaginaryI n(x))/(10x^(10)-6)=((-3sin(x))^(\prime)(10x^(10)-6)-(-3sin(x))(10x^(10)-6)^(\prime))/((10x^(10)-6)^2)`
`((-3cos(x))(10x^(10)-6)+(3s\imaginaryI n(x))(100x^9))/((10x^(10)-6)^2)`
`(-30x^(10)cos(x)+18cos(x)+300x^9sin(x))/((10x^(10)-6)^2)`