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A ball is dropped from a cliff and has an acceleration of 9.8 m/s^2 how long will it take the ball to reach a speed of 24.5 m/s

User Ammu
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Answer:

Acceleration of ball (a) = 9.8 m/s^2 Speed (v) = 24.5 m/s Time (t) = Acceleration / Time = v / a = 24.5/9.8 = 2.5 s So it will take 2.5 seconds to reach that speed.

Step-by-step explanation:

User Bert Bruynooghe
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Acceleration of ball (a) = 9.8 m/s^2 Speed (v) = 24.5 m/s Time (t) = Acceleration / Time = v / a = 24.5/9.8 = 2.5 s So it will take 2.5 seconds to reach that speed.
User Trashpanda
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