Question

A concave lens creates a virtualimage at -47.0 cm with amagnification of +1.75. What isthe object distance?(Mind your minus signs.)(Unit = cm)

Answer 1

Answer:

Object distance = 26.86 cm

Step-by-step explanation:

Given:

Image distance, v = -47.0 cm

Magnification, M = 1.75

Object distance, u = ?

`\begin{gathered} M=(|v|)/(|u|) \\ \\ 1.75=(47.0)/(u) \\ \\ u=(47.0)/(1.75) \\ \\ u=26.86\text{ cm} \\ \end{gathered}`

Object distance = 26.86 cm