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Find an equation of the circle that satisfies the given conditions:

Endpoints of a diameter are P(-1,3) and Q(7,-7)

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Given the two end of the diameter of the circle, we are able to compute the center of the circle as 0.5*[(-1,3)+(7,-7)]=(3,-2). The radius of the circle is 0.5*sqrt[(-1-7)^2+(3+7)^2]=sqrt(41). Therefore the equation of the circle is (x-3)^2+(y+2)^2=41.
User Artie
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