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A 700 g can of beans is dropped from a shelf that is 1.5 m high. What is the gravitational potential energy of this can? Round your answer to the nearest tenth of a joule.

_____ J.

User Simusid
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2 Answers

4 votes

Answer:

The gravitational potential energy of the can dropped from a shelf that is 1.5 m high, is 10.29 J. Rounding the answer to the nearest tenth of a joule, we have that the potential energy is 10.3 J.

Step-by-step explanation:

The potential gravitational energy can be written as


V=mgh

where m is the mass of the object, g is the gravitational acceleration, and h is the altitude of the object.

One thing we must understand is that V is a relative quantity, so we need to establish an altitude where V=0, in this case, the zero potential could be at the floor, so the altitude where the can is beeing dropped is h=1.5m.

Doing this, we have that


V=(0.7kg)*(9.8(m)/(s^2))*(1.5m)=10.29J

and when rounded, we have the final answer:


V=10.3J

User Matthew Coelho
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3 votes

Answer:10.3

Step-by-step explanation:

User Kederrac
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8.6k points