Question

Given the sequence [3,1,-1,-3], find a32.

Answer 1

-59

Step-by-step explanation:

Given the sequence:

`3,1,-1,-3`

• The first term, a=3

,

• The common difference = 1-3=-2

The nth term of an arithmetic sequence is obtained using the formula:

`a_n=a+(n-1)d`

In this case: n=32

Therefore:

`\begin{gathered} a_(32)=3+(32-1)(-2) \\ =3+(31)(-2) \\ =3+(-62) \\ =3-62 \\ a_(32)=-59 \end{gathered}`

The 32nd term of the sequence is -59.