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Please help me with my math homework! 20 points!

A culture of 1.08×10^15 bacteria is in petri dish A. A culture of 2.7×10^11 bacteria is in petri dish B.

How many times greater is the number of bacteria in petri dish A than petri dish B?

Enter your answer, in standard notation, in the box.

1 Answer

5 votes

To find the number of times the bacteria in petri dish A than petri dish B, let us divide.

So, number of times =
(Number of times bacteria in petri dish A)/(Number of times bacteria in petri dish B)


= (1.08(10^(15) ))/(2.7(10^(11) ))

= 0.4 ×
10^(4)

= 4000

Hence, the number of bacteria in petri dish A is 4000 times the number of bacteria in petri dish B.

User Mitchel Verschoof
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