Y=f(x) is odd (f(-x)=-f(x)) and f(x>0) = x^2-5x-12, x is not = to 0. What points does the line f(x)=12 go through.

asked Dec 7, 2018 75.1k views

1 vote

y=f(x) is odd (f(-x)=-f(x)) and f(x>0) = x^2-5x-12, x is not = to 0. What points does the line f(x)=12 go through.

8.9k points

0 Comments

Please log in or register to add a comment.

3 votes

f(x<0)=-f(x>0)=-x^2+5x+12 When x>0, x^2-5x-12=12, x=8, y=12 Therefore, f(x)=12 goes through point (8,12).

LeMike answered Dec 10, 2018

8.6k points

0 Comments

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers