Register
Solve x3 = 125 over 27. 25 over 9 ą25 over 9 5 over 3 ą5 over 3
223k views
5 votes
Solve x3 = 125 over 27. 25 over 9 ą25 over 9 5 over 3 ą5 over 3

User Anju Aravind
by
7.5k points

1 Answer

0 votes
x^3 = 125/27

Real solution:
x = (125/27)^(1/3) = 5/3

NOTE: -5/3 is not a solution, because
(-5/3)^3 = (-5/3) * (-5/3) * (-5/3) = -125/27
User Nandanself
by
7.7k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement  how thick must the cement be to cover field
Write words to match the expression. 24- ( 6+3)
Link Copied!