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33 votes
In triangle CDE,m angle C=52,m angle D=17 , and e = 29.6 . Find c to the nearest tenth

User Mera
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1 Answer

9 votes
9 votes

The triangle can be drawn as,

The value of angle E can be determined as,


\begin{gathered} 17+52+\angle E=180 \\ \angle E=111^(\circ) \end{gathered}

The value of c can be determined from the sine rule as,


\begin{gathered} (e)/(\sin E)=(c)/(sinC) \\ (29.6)/(\sin 111^(\circ))=(c)/(\sin 52^(\circ)) \\ c=24.98 \\ \approx25.0 \end{gathered}

Thus, the value of c to the nearest tenth is 25.0.

In triangle CDE,m angle C=52,m angle D=17 , and e = 29.6 . Find c to the nearest tenth-example-1
User Joshua Wooward
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