In this question, we have to find the missing value in a dilution situation, the formula of dilution is:
M1*V1 = M2*V2
For letter A, we have:
M1 = 3.0 M of NaCl
V1 = ?
M2 = 0.5 M of NaCl
V2 = 600 mL
Now we add these values into the formula:
3 * V1 = 0.5 * 600
V1 = 100 mL, this if for LETTER A
For letter B, we have:
M1 = 2.5 M of MgSO4
V1 = ?
M2 = 0.2 M
V2 = 1.0 L or 1000 mL
Now we add these values into the formula:
2.5 * V1 = 0.2 * 1000
V1 = 80 mL, this is for LETTER B
For letter C, we have:
M1 = 4.8 M KNO3
V1 = ?
M2 = 0.2 M
V2 = 80 mL
Now we add these values into the formula:
4.8 * V1 = 0.2 * 80
V1 = 3.33 mL, this is for LETTER C