Question

Round to the nearest hundredth what is the positive solution to the quadratic equation 0 = 2x^2 + 3x -8

Answer 1

Answer: the guy above is right for anyone looking at this and was sceptical

Explanation:

Answer 2

We can use the quadratic formula to solve the quadratic equation

Quadratic formula is given by

`x_1= (-b+ √(b^2-4ac) )/(2a)`, and

`x_2= (-b- √(b^2-4ac) )/(2a)`

We are given
`2x^2+3x-8=0`, where:

`a=2`,
`b=3`, and
`c=-8`

Substitute the values of
`a, b, c` into the formula:

`x_1= (-3+ √(3^2-4(2)(-8)) )/(2(2))=1.39` (rounded to two decimal places)

`x_2= (-3- √(3^2-4(2)(-8)) )/(2(2))=-2.89` (rounded to two decimal places)

The positive solution is x = 1.39