Question

Please help me solve this maths problem ☺

Answer 1

lets

h =# of hens in the filed and c = # of cows in

the field

hens and cows have 50 heads

h + c = 50 (1)

hens and cows have 180 legs (hen has 2

legs and cow has 4 legs)

2h+4c180 (2)

From equation (1) h + c = 50 ----> h = 50 - c

substitute h = 50 c into 2h + 4c = 180 (

-

2h+4c 180

2(50-c) + 4c = 180

1002c+ 4c = 180

2c 180-100

2c=80

C = 40

2h + 4(40) = 180

2h+160 180

2h = 20

h = 10

answer

hens = 10 and cows = 40

double check:

heads: 10 hens + 40 cows = 50 total legs:10(2) + 40(4) = 20 + 160 = 180

Answer 2

lets
h =# of hens in the filed and c = # of cows in the field

hens and cows have 50 heads
h + c = 50 (1)

hens and cows have 180 legs (hen has 2 legs and cow has 4 legs)
2h + 4c = 180 (2)

From equation (1) h + c = 50 ----> h = 50 - c

substitute h = 50 - c into 2h + 4c = 180 (
2h + 4c =180
2(50 - c) + 4c = 180
100 - 2c + 4c = 180
2c = 180 - 100
2c = 80
c = 40

2h + 4(40) = 180
2h + 160 = 180
2h = 20
h = 10

answer
hens = 10 and cows = 40

double check:
heads: 10 hens + 40 cows = 50 total
legs:10(2) + 40(4) = 20 + 160 = 180