Question

Consider the following equation of a circle find the radius, r

Answer 1

Given:

There are given the equation:

`x^2+y^2-4x+4y+4=0`

Step-by-step explanation:

To find the radius of the circle, first, we need to write the given equation into the vertex for:

Then,

`\begin{gathered} x^(2)+y^(2)-4x+4y+4=0 \\ (x-2)^2+(y+2)^2=2^2 \end{gathered}`

Final answer:

According to the vertex form of the circle:

The value of the radius is 2.