Question

A boy throws a baseball across a field. The ball reaches its maximum height, 18 meters, after 1 second. After approximately 2.3 seconds, the ball lands on the ground. The ball’s motion can be modeled using the function f(x) = –10x2 + 20x + 8. What is the height of the ball 1.5 seconds after it is thrown?

Answer 1

It is c on edge just took the test

Explanation:

Answer 2

Explanation:

Alright, lets get started.

The function that models the height of the ball is given by :

`f(x)=-10x^2+20x+8`

When we plug x as 1.5 , we could get the height f(1.5) as :

`f(1.5)=-10(1.5)^2 +20*1.5 +8`

`f(1.5)=-22.5+30+8`

`f(1.5)=15.5`

So the height of the ball after 1.5 second is 15.5 meters. : Answer

Hope it will help :)