Question

You reach into a bag of coins and withdrew two coins without replacement. What is the probability you withdrew a nickel and then a dime if the bag held ten pennies, six nickels, and five dimes?

1.30/44
2.5/14
3.1/14

Answer 1

Option 3. 1/14

Explanation:

The bag held some coins that are

pennies = 10

nickels = 6

dimes = 5

total coins = 10 + 6 + 5 = 21 coins

You drew 2 coins without replacement,

so the probability that first draw will be nickel =
`P_(1)` = 6/21 = 2/7

Second draw will be a dime =
`P_(2)` = 5/20 = 1/4

P =
`(2)/(7)` ×
`(1)/(4)` = 2/28 = 1/14

Option 3. 1/14 would be the answer.