Question

Grams, Moles, Atoms, MoleculesShow calculation setups, including units, and enter answers with correct significant figures andunits on the line(s) provided.1. Find the molar mass to 3 decimal places of (a) magnesium sulfate, (b) diphosphorus heptoxide,and (c) iron(III) hydroxide. Use these values as needed in problems 2-4,(b)(c)

Answer 1

Step-by-step explanation

(a) magnesium sulfate.

The chemical formula for magnesium sulfate is MgSO₄

From the Periodic table, the Molar Mass of:

Mg = 24.305 g/mol

O = 15.999 g/mol

S = 32.065 g/mol

So, the molar mass of MgSO₄ is calculated as follows:

MgSO₄ = (Mg + S + (4 x O))

MgSO₄ = (24.305 + 32.065 + (4 x 15.999)) g/mol

MgSO₄ = (56.37 + 63.996) g/mol

MgSO₄ = 120.366 g/mol

The molar mass of magnesium sulfate (MgSO₄) is 120.366 g/mol.

(b) diphosphorus heptoxide.

The chemical formula for diphosphorus heptoxide is P₂O₇

From the Periodic table, the Molar Mass of:

P = 30.973762 g/mol

O = 15.999 g/mol

So, the molar mass of P₂O₇ is calculated as follows:

P₂O₇ = 2(P) + 7(O)

P₂O₇ = ((2 x 30.973762) + (7 x 15.999)) g/mol

P₂O₇ = (61.947524 + 111.993) g/mol

P₂O₇ = 173.941 g/mol

The molar mass of diphosphorus heptoxide (P₂O₇) is 173.941 g/mol.

(c) iron (III) hydroxide.

The chemical formula for iron (III) hydroxide is Fe(OH)₃.

From the Periodic table, the Molar Mass of:

H = 1.00784 g/mol

O = 15.999 g/mol

Fe = 55.845 g/mol

So, the molar mass of Fe(OH)₃ is calculated as follows:

Fe(OH)₃ = Fe + 3(O) + 3(H)

Fe(OH)₃ = (55.845 + 3(15.999) + 3(1.00784)) g/mol

Fe(OH)₃ = (55.845 + 47.997 + 3.02352) g/mol

Fe(OH)₃ = 106.866 g/mol.

The molar mass of iron (III) hydroxide (Fe(OH)₃) is 106.866 g/mol.