Question

Car X leaves Northtown traveling at a steady rate of 55 mph.  Car Y leaves 1 hour later following Car X, traveling at a steady rate of 60 mph.  Which equation can be used to determine how long after Car X leaves Car Y will catch up?

Answer 1

Unfortunately, you haven't shared the equations from which you're supposed to choose your answer.

But we can write our own.

When will the distance traveled by the 1st car = the distance traveled by the 2nd car?

55 miles + (55 mph)x = (60 mph)x

solve this for x: 55 miles = (60-55)x mph = 5 mph

x=11 hours

The two cars are the same distance from the starting point after 11 hours.