Question

2x - y - 4 = 0

3x + y - 9 = 0

What is the solution set of the given system?

(A.) {(6/5, 13/5)}
(B.) {(13/5, 6/5)}
(C.) {(5, 6)}
(D.) {(6, 5)}

Answer 1

So to start you should get x and y on the same side and get the numbers on one side. Then you should cancel out a variable. Because both y’s are 1 and they are opposite charges they will both cancel out to 0. Then add what is remaining which is the 2x and the 3x and equal that to +9-4 which equals 5. You want x to be all by itself so you would divide both sides by 5 and get that x=1. Then you would just substitue and solve for y. Hope this helped!

Answer 2

2x-y=4
3x+y=9

5x=13

x=13/5

3(13/5)+y=9

39/5+y=45/5

y=45/5-39/5

y=6/5

the answer is b