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A trapezoid has an area of 20 cm2 and a height z cm. The lengths of the parallel sides are (2z + 3) cm and (6z – 1) cm. Find the height, z, of the trapezoid. In your final answer, include all of the formulas and calculations necessary.

User Vptheron
by
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2 Answers

3 votes
check the picture below.


\bf A=\cfrac{h(a+b)}{2}\quad \begin{cases} A=20\\ a=6z-1\\ b=2z+3\\ h=z \end{cases}\implies 20=\cfrac{z[(6z-1)~+~(2z+3)]}{2} \\\\\\ 20=\cfrac{z(8z+2)}{2}\implies 20=\cfrac{2z(4z+1)}{2}\implies 20=z(4z+1) \\\\\\ 20=4z^2+z\implies 0=4z^2+z-20


\bf \qquad \qquad \textit{quadratic formula}\\\\ \begin{array}{llccll} 0=&{{ 4}}z^2&{{ +1}}x&{{ -20}}\\ &\uparrow &\uparrow &\uparrow \\ &a&b&c \end{array} \qquad \qquad z= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}} \\\\\\ z=\cfrac{-1\pm√(1+320)}{8}\implies z=\cfrac{-1\pm√(321)}{8}\implies z\approx \begin{cases} \boxed{2.1146}\\ -2.3646 \end{cases}

since the height is just a length unit, it can't be -2.3646.
A trapezoid has an area of 20 cm2 and a height z cm. The lengths of the parallel sides-example-1
User FThompson
by
8.5k points
4 votes

Answer:

2.11 cm

Explanation:

As you can see in the picture I put the sides in the trapezoid. Now, let's use the area's formula:

A =
((B+b)*h)/(2)

where B is the Largest parallel side, b the smallest parallel side and h is the height.

Now,

20 =
((6z-1+2z+3)*z)/(2)

20 =
((8z^(2)+2z)/(2)

20 =
4z^(2)+z


4z^(2)+z-20=0

Then, we use the cuadratic formula z=
\frac{-b+-\sqrt{b^(2)-4ac} }{2a} where a=4, b=1 and c=-20.

z=
(-1+-√(1-4(4)(-20)) )/(8)

z =
(-1+-√(1+320) )/(8)

z =
(-1+-√(1+320) )/(8)

z =
(-1+-17.91)/(8)

As we are searching lenght we choose the positive z value

z =
(-1+17.91)/(8)

z=
(16.91)/(8)

z = 2.11 cm.

User Powder
by
8.8k points