Question

The expression to find the perimeter of a rectangle is 2(length + width). What is the perimeter, in units, of a rectangle of length fraction 1 over 7 unit and width fraction 1 over 2 unit?

Answer 1

P = 2(L + W)
L = 1/7
W = 1/2

P = 2(L + W)
P = 2(1/7 + 1/2)
P = 2(2/14 + 7/14)
P = 2(9/14)
P = 18/14 which reduces to 9/7 or 1 2/9 <==

Answer 2

perimeter of rectangle is 9/7 units.

Explanation:

The perimeter of a rectangle is given by

Perimeter = 2(length + width)

Given that

`length=(1)/(7)\\\\width=(1)/(2)`

Substituting these values in the above formula

`P=2((1)/(7)+(1)/(2))`

Add the fractions. The LCD is 14. So, multiply and divide by 14

`P=(2)/(14)((1)/(7)*14+(1)/(2)*14)\\\\P=(1)/(7)(2+7)\\\\P=(9)/(7)`

Thus, perimeter of rectangle is 9/7 units.